If P(E)=0.05, what is the probability of ‘not E’?
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P(E) +P(NOT E) =1
P(E) = 0.05
0.05+P(NOT E) = 1
P(NOT E) = 1- 0.05
P(NOT E) = 0.95
probability of 'not E' is 0.95
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Answer:
probability P(E)=0.05 probability of not happening the event A = P(E') now we know that P(E) +P(E')=1 hence P(E')=1-- P(E) = 1-0.05=0.95
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