Question

if P(E) =0.09, then the probability of not'E' is​

Answer 1

Answer:

1-0.09=0.91

Step-by-step explanation:

P(E)+P(E)'=1

given P(E)=0.09

then P(E)'=1-0.09

=0.91

Answer 2

Answer:

$\large\bf\underline\red{Question ➡} \\ \\ \bf \: if \: P(E) \: = 0.09 \: then \: \\\bf find \: P(Ē) \\ \\ \large\bf\underline\red{solution ➡} \\ \\ \bf\blue{ \: \: P(E) + P(Ē) = 1} \\ \\ \bf0.09 + P(Ē) = 1 \\ \\ \bf \: P(Ē) = 1 - 0.09 \\ \\\bf = 0.91$