Question

If P E( ) 0.12  then find P(E)​

Answer 1

SOLUTION

GIVEN

$\sf{P( \overline{E}) = 0.12 }$

TO DETERMINE

$\sf{P( {E}) }$

CONCEPT TO BE IMPLEMENTED

In any random experiment if the total number of elementary ( simple) events in the sample space be n ( a finite number) among which the number of elementary events favourable to an event E , connected with the experiment be m then the probability of the event E is denoted by P (E) and defined as

$\displaystyle \sf{}P(E) = \frac{m}{n}$

$\sf{ \therefore \: \: P( \overline{E}) = 1 - P( {E}) }$

EVALUATION

Here it is given that

$\sf{P( \overline{E}) = 0.12}$

So From above we have

$\sf{P( \overline{E}) = 1 - P( {E}) }$

$\sf{ \implies \: 0.12 = 1 - P( {E}) }$

$\sf{ \implies \: P( {E}) = 1 - 0.12 }$

$\sf{ \implies \: P( {E}) = 0.88 }$

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