Question

if p(e)=0.20,then what is the probability of "not E"

Answer 1

since P(E)=0.20 then
P(E)-P(E')=1
therefore 0.20-P(E')=1
P(E')= 1 - 0.20
P(E')= 0.8
hope this helps you ^_^

Answer 2

Answer:

0.8 is the answer

Step-by-step explanation:

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