Math, asked by Rashiv3392, 7 months ago

If p(e) =0.36 what is the probability of 'not e'

Answers

Answered by nikhiliasaim

1

Answer:

0.64

Step-by-step explanation:

p(e) = 0.36

possible probability = 1

p(not e) = 1 - 0.36

= 0.64

Answered by LiarHeart

0

Step-by-step explanation:

P(E)=0.05

P(notE)=1−0.05=0.95

✌✌

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