Math, asked by gunenderchauhan7723, 10 months ago

If P(E)=0.65,What is the probability of 'not E'?

Answers

Answered by mahitha14
2

Answer:

0.35

Step-by-step explanation:

P(Ē)=1-P(E)

=1-0.65

=0.35

Answered by LiarHeart
0

Step-by-step explanation:

We know that the sum of the probabilities of all the elementary events of an experiment is 1.

If an experiment has two elementary events say E & not E then,

P(E)+P(notE)=1⟹P(notE)=1−P(E)

Given P(E)=0.05

∴P(notE)=1−0.05=0.95

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