If P(E)=0.65, what is the probability of 'note'
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Probability of having, P (E) = 0.65
As we know that
Probability of having + Probability of not = 1
Probability of not = 1 - Probability of having
= 1 - 0.65
= 0.35
Hope it will help you
As we know that
Probability of having + Probability of not = 1
Probability of not = 1 - Probability of having
= 1 - 0.65
= 0.35
Hope it will help you
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