Question

if P(E)=0.992, what is the probability of"Not E"

Answer 1

If P(E) = 0.992 then the probability of not E is 0.008

Given :

P(E) = 0.992

To find :

The probability of not E

Solution :

Step 1 of 2 :

Write down the given probability

Here it is given that for the event E

P(E) = 0.992

Step 2 of 2 :

Find probability of not E

We know that for any event E ,

P(E) + P(not E) = 1

In order words P(E) + P(E') = 1

Thus we get

P(E) + P(not E) = 1

⇒ 0.992 + P(not E) = 1

⇒ P(not E) = 1 - 0.992

⇒ P(not E) = 0.008

Hence the required probability of not E = 0.008

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Answer 2

Answer:

The Probability of "Not E" is denoted by P(E') = 1 - P(E)= 1 - 0.992 = 0.008

Step-by-step explanation:

Probability:

Probability is the measure of the likelihood of an event to occur.

  Let E be an event then

• Probability of the event to occur is denoted by P(E).

• Probability of an event cannot occur is denoted by P(E').

• The Probability of all events is equal to 1.

              P(E) + P(E') = 1   ------(i)

• Given P(E) = 0.992

          substitute the value of P(E) in the above equation (i)

          then we get P(event cannot occur) = P(E')

                       0.992 + P(E') = 1

                                      P(E') = 1 - 0.992

                                              = 0.008

             Hence, Probability of "Not E" = 0.882

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