Math, asked by sunitha1983, 11 months ago

if p(e) =1, probability of not e=?​

Answers

Answered by Evv
1

Answer:

Step-by-step explanation:

Answer is zero (0)

Attachments:
Answered by Uniquedosti00017
2

Answer:

since

p(e) + p( not e) = 1

=> 1 + p( not e ) = 1

=> p( not e ) = 0

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