Math, asked by dollysrivastava1973, 10 months ago



If P (E) = 3x 1 and P (not E) = 7x-2. Find the value of x.

Answers

Answered by choudharyrekha022
1

Answer:

p(e)+p(not e) =0

(3x+1)+(7x-2)=0

4x-1=0

4x=1

x=1/4

I hope your problem is solved

plzz give response with thanked

Answered by classofankur
0

Answer:

p(e) + p(not e) = 1

so 3x + 1 + 7x - 2 = 1 (assuming you mean p (e) = (3x + 1)

10x - 1 = 1

10x = 1 + 1

x = 2/10 = 0.2

Similar questions