# if p>2 and p belongs to N, then the equation x cube -px+1=0 cannot have

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let p> and = 2 than p =2

x^2 -2x+1 =0

x^2 -1x - x +1

x(x -1) -1( x -1)

(x-1)(x-1) =0

x =1

so x cannot have 1

x^2 -2x+1 =0

x^2 -1x - x +1

x(x -1) -1( x -1)

(x-1)(x-1) =0

x =1

so x cannot have 1

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