if p>2 and p belongs to N, then the equation x cube -px+1=0 cannot have
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let p> and = 2 than p =2
x^2 -2x+1 =0
x^2 -1x - x +1
x(x -1) -1( x -1)
(x-1)(x-1) =0
x =1
so x cannot have 1
x^2 -2x+1 =0
x^2 -1x - x +1
x(x -1) -1( x -1)
(x-1)(x-1) =0
x =1
so x cannot have 1
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