Question

if P=i+2j+6k , its direction cosines are
1
6
0
1)
12.
and
41 41 41
2)
and
4141
이념
3 8
7
4141
4) 1,2 and 6
V41​

Answer 1

Answer:

1/√41,2/√41 and 6/√41

Explanation:

sure this is exact answer

Answer 2

Given

P=i+2j+6k

Comparing with the general vector form (P=ai+bj+ck)

a=1

b=2

c=6

Direction cosines are given by:

Along X direction:

$\frac{1}{\sqrt{1^{2}+2^{2} +6^{2} } }$

=$\frac{1}{\sqrt{41} }$

Along Y direction:

$\frac{2}{\sqrt{1^{2}+2^{2} +6^{2} } }$

=$\frac{2}{\sqrt{41} }$

Along Z direction:

$\frac{6}{\sqrt{1^{2}+2^{2} +6^{2} } }$

=$\frac{6}{\sqrt{41} }$