Question

if p is -15=13-p find p​

Answer 1

Answer:

We know that while finding the root of a quadratic equation ax2+bx+c=0 by quadratic formula x=2a−b±b2−4ac, 

if b2−4ac>0, then the roots are real and distinct 

if b2−4ac=0, then the roots are real and equal and

if b2−4ac<0, then the roots are imaginary.

Here, the given quadratic equation pk2−12k+9=0 is in the form ax2+bx+c=0 where a=p,b=−12 and c=9.

  

It is given that the roots are equal, therefore b2−4ac=0 that is:

b2−4ac=0⇒(−12)2−(4×p×9)=0⇒144−36p=0⇒−36p=−144⇒36p=144⇒p=36144⇒p=4  

Hence, p=4

Explanation:

I hope it will be help you

Answer 2

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-15 = 13 - p

-15 - 13 = p

28 = p

p = 28

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