if p is a point inside a rectangle ABCD then A.ap^2+PC^=BP^2+pd^2. B.ap+pc=bp+pd c.ap×pc=bp×pd
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ABCD is a rectangle and O is any point in the plane (within the rectangle). Prove: OA2 + OC2 = OB2 + OD2. Solution: F. B. C. E. G. A. H. D. O. Draw rectangle ABCD with arbitrary point O within it, and then draw lines OA, OB, OC, OD. Then draw lines from point O perpendicular to the sides: OE, OF, OG, OH.
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