If P is a point on side CD of a square ABCD such that PC= 5 cm . If area of triangle ADP is 42 cm square . Then length of the side square is
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Each side of a square ABCD is 12 cm. A point P lies on side CD such that area of ΔADP : area of trapezium ABCP = 2 : 3. Find DP. A . 9.6 cm.
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