Question

If P is a point on y-axis , whose ordinate is 3 and Q is a point (-5,2) , then the distance PQ is???

Answer 1

Answer:

P is ( 0 , 3 ) . Q is ( -5 , 2 )

So

$d = \sqrt{(0 - ( - 5)) {}^{2} + {(3 - 2)}^{2} } \\ \\ = \sqrt{25 + 1} \\ \\ = \sqrt{26}$

Answer 2

The distance is $\sqrt{26}$ units.

Step-by-step explanation:

A point on the y-axis always has the x-coordinate equal to zero.

Now, if P is a point on the y-axis, whose ordinate i.e. y-coordinate is 3, then the point will be given by (0,3).

Therefore, the distance between the point P(0,3) and another given point Q(-5,2) will be

= $\sqrt{(0 + 5)^{2} + (3 - 2)^{2}} = \sqrt{26}$ units. (Answer)

Note: We know the distance formula between two-points with know coordinates $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$.