If P is a point plotted on graph paper and we have to find the abscissa and ordinate of point P. Draw perpendiculars PM and PN from P to X-axis and Y-axis, respectively.
PN = -2 units (distance from X-axis, i.e. x-coordinate or abscissa)
PM = 9 units (distance from Y-axis, i.e. y-coordinate or ordinate)
As, point P lies in second quadrant.
So, the coordinates of P are (- 2,9).

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