If p is a prime no. Them prove that √p is irrational
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p is a prime no.
The prime no. are 2,3,5,7.......
To prove:- root p i.e., root 2 , root 3 etc.
Now let root 2 be rational no. so it is in the is of a/b where a and b is a co-prime no. it means there is no other 1 and itself.
a/b= 2
a= b root 2
Squaring on both side,
(a)^2=(b root2)^2
a^2= 2b^2................ (1)
If p is a prime no. and p divides a^2 then it divides a also where a is positive integer.
a=2c
Squaring on both side
a^2=4c^2
Substitute eq (1)
2b^2=4c^2
b^2=2c^2
If p is a prime no. and p divides a^2 thenp divides a , where a is positive integer.
We considered there is no other common factor than 1 and itself but there is . so root 2 is irrational
root 2 is prime no. so root p also irrational number
Proved
The prime no. are 2,3,5,7.......
To prove:- root p i.e., root 2 , root 3 etc.
Now let root 2 be rational no. so it is in the is of a/b where a and b is a co-prime no. it means there is no other 1 and itself.
a/b= 2
a= b root 2
Squaring on both side,
(a)^2=(b root2)^2
a^2= 2b^2................ (1)
If p is a prime no. and p divides a^2 then it divides a also where a is positive integer.
a=2c
Squaring on both side
a^2=4c^2
Substitute eq (1)
2b^2=4c^2
b^2=2c^2
If p is a prime no. and p divides a^2 thenp divides a , where a is positive integer.
We considered there is no other common factor than 1 and itself but there is . so root 2 is irrational
root 2 is prime no. so root p also irrational number
Proved
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