If p is a prime number prove that root p is irrational? It's a 4 mark question
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Let √p be a rational number.
Let,√p=a/b,where a and b are integers and b is not = 0.
Then,√p=a/b
Squaring both sides,
(√p)2/1 = (a/b)2
p/1=a2/b2
pb2=a2. (Equation 1)
Therefore,p divides a2.
p divides a also.
Let,a=bq for some integer q.
Put a=bq in equation 1,
pb2=p2q2
b2=pq2
Therefore,p divides b2.
p divides b also.
Thus,p is a common factor of a and b.
So,our assumption is not correct.
Hence,√p is an irrational number.
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