if p is a prime number then prove that √p is irrational.
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Answer:
Let p be a rational number and
p
=
b
a
⇒p=
b
2
a
2
⇒a
2
=pb
2
∴p divides a
2
But when a prime number divides the product of two numbers, it must divide atleast one of them.
here a
2
=a×a
p divides a
Let a=pk ......(1)
(pk)
2
=pb
2
⇒p
2
k
2
=pb
2
⇒b
2
=pk
2
∴p divides b
2
But b
2
=b×b
∴p divides b
Thus, a and b have atleast one common multiple p
But it arises the contradiction to our assumption that a and b are co prime.
Thus, our assumption is wrong and
p
is irrational number.
Step-by-step explanation:
Hope this helped u friend
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