. If p is an even number then write its three consecutive even integers.
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1
Answer:
Let the first even number = x
second even number = x + 2
and third even number = x + 4
According to the condition,
x+x+2+x+4=54x+x+2+x+4=54
⇒3x+6=54⇒3x+6=54
⇒3x=54-6⇒3x=54−6
⇒x=\frac{48}{3}⇒x=
3
48
⇒x=16⇒x=16
∴ First even number =x= 16
Second even number = x+2 = 16 + 2 = 18
and third even number = x+3 = 16 + 4 = 20
Hence, the three consecutive even numbers are 16, 18 and 20.
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