If p is an odd prime, then prove that summation(a|p)=0.
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Hello Radhe Radhe
☺☺☺☺☺
Step-by-step explanation:
Prove, if p is an odd prime: 1p−1+2p−1+...+(p−1)p−1 is congruent to -1 modulo p.
I was going to try and show this by induction but I am having trouble with the base case that 1p−1≡−1 mod p. This makes me think that induction isn't the right way to go. Any help would be much appreciated.
Thank you!
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