Question

if P is equals to 2 minus A then prove that a cube + 68 + b cube minus 8 is equals to zero​

Answer 1

Hi mate,

here is your answer

It is given that ,

p = 2 - a -------( 1 )

LHS = a³ + 6ap + p³ - 8

= a³ + 6a( 2 - a ) + ( 2-a )³ - 8 [ from(1)]

= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8

= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8

= 0

= RHS

Hence proved.

I hope this helps you

Answer 2

Answer:

Here I have attached one pic of the answer.

Hope it helps u.

Plz mark me as brainlist

Also give me five star rating

And also tap the thanks button.

Here is the attachment.

Thank u. :)