if P is equals to under root minus under root 2 upon under root 3 + under root 2 and q is equals to under root 3 + under root 2 upon under root 3 minus under root 2 then find p square + Q square
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GIVEN That
p=√3-2/√3+2
q=√3+2/√3-2
We know that,
(p + q)² = p² + q² + 2pq
=> (p + q)² - 2pq = p² + q²
=> p² + q² = (p + q)² - 2pq
Putting value of (p+q)² and pq in (1)
We get,
p² + q² = 100-2×1 = 100-2 = 98
=> p² + q² = 98
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