Question

If 'P' is in equilibrium then T1/T2 is

Answer 1

Answer:

1 / $\sqrt3$

Explanation:

Since T1 makes angle 30° and T2 makes angle 60° with the horizontal we have,

T1 cos Θ1 = T2 cos Θ2

⇒T1 cos 30° = T2 cos 60°

⇒T1 ($\sqrt3$/2) = T2 (1/2)

Taking T2 to left hand side,

⇒T1 / T2 = 1 / √3

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Answer 2

Given:

P is in equilibrium in presence of T1 and T2.

To find:

Value of T1/T2.

Calculation:

Applying Lami's Theorem, we get:

$\dfrac{T1}{ \sin( {90 }^{ \circ} + {60}^{ \circ} ) } = \dfrac{T2}{ \sin( {90 }^{ \circ} + {30}^{ \circ} ) } = 900$

Considering the first two variables:

$= > \dfrac{T1}{ \cos( {60}^{ \circ} ) } = \dfrac{T2}{ \cos( {30}^{ \circ} ) }$

$= > \dfrac{T1}{ T2} = \dfrac{ \cos( {60}^{ \circ} ) }{ \cos( {30}^{ \circ} ) }$

$= > \dfrac{T1}{ T2} = \dfrac{ ( \frac{1}{2} )}{ ( \frac{ \sqrt{3} }{2}) }$

$= > \dfrac{T1}{ T2} = \dfrac{1}{ \sqrt{3} }$

So, final answer is:

$\boxed{ \red{ \bold{ \large{\dfrac{T1}{ T2} = \dfrac{1}{ \sqrt{3} } }}}}$