if p is priem number then √2 is
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Ok Thanks!
Step-by-step explanation:
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Step-by-step explanation:
If possible,let √p be a rational number. also a and b is rational. then,√p = a/b on squaring both sides,we get, (√p)²= a²/b²
Thus, a and b have atleast one common multiple p
But it arises the contradiction to our assumption that a and b are coprime.
Thus, our assumption is wrong and p
is irrational number.
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