Question

If P is the mid point of the line segment joining the points A and B then write coordinates of point P A(-2-3 p B{ 2,੩)?
1) (4,6) 2) (0,6) 3) (4,0) 4) (0,0)​

Answer 1

${ \huge\tt Question}$

If P is the mid point of the line segment joining the points A and B then write coordinates of point P when A (-2,-3) B (2,3).

$\huge \orange{ \frak Answer}$

Option (4) is correct i.e the coordinates of P (0,0)

Solution

It is given that the line segment AB has a midpoint P , A having coordinates (-2,-3) and B have coordinates (2,3) , in order to find the coordinates of P apply Mid - point Formula .

Let the co-ordinates of P be ( x , y ) .

and let the coordinates of A ( -2 , -3 ) and

B ( 2, 3 ) be represented as following respectively.

$\tt(x_1y_1) \&(x_2y_2)$

☯︎ Apply Mid point Formula.

$\sf( x , y ) = ( \dfrac{x_1 + x_2}{2} ,\dfrac{y_1 + y_2}{2} )$

On Implementation ,

$: \implies \tt(x,y) = ( \dfrac{ - 2 + 2}{2} ,\dfrac{ - 3 + 3}{2}) \\ = ( \dfrac{0}{2} , \dfrac{0}{2}) = \colorbox{red}{ (0,0)}$

☯︎ Conclusion

The coordinates of P is ( 0 , 0 ) implies that the origin is itself the midpoint of the line segment AB .

Thankyou

Answer 2

Answer:

woooooo

Step-by-step explanation:

so,

(-2+2/2),(-3+3/2)

(0/2),(0/2)

(0),(0)

so,

option 4 is the correct answer .....

i m also in 10th std...