If p is the momentum of an object of mass m the expression p^2/ 2m has bade units equal to:
(A) Energy
(B) Power
(C) Force
(D) velocity
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We know that ,
p² = m² × v² , Since p = mv
substituting p² value from above equation and dividing by 2 m
![\frac{ {m}^{2} \times v {}^{2} }{2m} \\ \\ = \frac{1}{2} \times mv {}^{2} \frac{ {m}^{2} \times v {}^{2} }{2m} \\ \\ = \frac{1}{2} \times mv {}^{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%7Bm%7D%5E%7B2%7D++%5Ctimes+v+%7B%7D%5E%7B2%7D+%7D%7B2m%7D++%5C%5C++%5C%5C++%3D++%5Cfrac%7B1%7D%7B2%7D++%5Ctimes+mv+%7B%7D%5E%7B2%7D+)
We got the equation of Kinetic Energy!
➡➡➡ So your answer is ( A ) Energy ✔✔✔
p² = m² × v² , Since p = mv
substituting p² value from above equation and dividing by 2 m
We got the equation of Kinetic Energy!
➡➡➡ So your answer is ( A ) Energy ✔✔✔
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