if p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having
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Solution:- (D) 94λ
hv−ϕ=KE
⇒(λhc)incident=KE+ϕ
(λhc)incident≃KE
KE=2mp2=λincidenthc=λhc ...(1)
⇒2mp2×(1.5)2=λ′hc ...(2)
divide (1) and (2)
(1.5)2=λ′λ
⇒λ′=94λ
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