Question

if p is the point of trisection of the line segment AB then it divides AB in the ratio​

Answer 1

The point P divides AB in the ratio of 1 : 2.

Step-by-step explanation:

Given that P is a point on line segment AB and it trisection the line segment AB.

Therefore, $AP = \frac{1}{3}(AB)$

So, we can write BP = AB - AP  

⇒ $BP = AB - \frac{1}{3}AB$

⇒ $BP = \frac{2}{3}AB$

Hence, the ratio of AP and BP is $\frac{1}{3}AB : \frac{2}{3}AB$ = 1 : 2.

Therefore, the point P divides AB in the ratio of 1 : 2. (Answer)