Question

If p = log^a bc, q=log^b ca, r=log^c ab, then pqr = pls anyone only correct answer please​

Answer 1

Answer:

pqr=(logab+logac)(logbc+logba)(logca+logcb)pqr=(logab+logac)(logbc+logba)(logca+logcb)

=(logac+1+logac.logbc+logbc)(logca+logcb)=(logac+1+logac.logbc+logbc)(logca+logcb)

=1+logab+logca+logcb+logbc+logac+logba+1=1+logab+logca+logcb+logbc+logac+logba+1

=2+(logab+logac)+(logca+logcb)+(logbc+logba)=2+(logab+logac)+(logca+logcb)+(logbc+logba)

=2+logabc+logbac+logcab=2+logabc+logbac+logcab

=2+p+q+r=2+p+q+r.