Question

if p (m) = 2+m+2m²-m³. f in ND the value of p (2)​

Answer 1

Given that,

P(m)=m

3

+2m

2

−m+10

P(a)+P(−a)=[a

3

+2a

2

−a+10]+[(−a)

3

+2(−a)

2

−(−a)+10]

=a

3

+2a

2

−a+10+[−a

3

+2a

2

+a+10]

=a

3

+2a

2

−a+10−a

3

+2a

2

+a+10

=4a

2

+20

Answer 2

Answer:

Given p (m) = 2+m+2m²-m³

we have to find p(2)

Substitute m = 2 in p(m) we get

p(2) = 2 + 2 + 2(2*2) - (2*2*2)

p(2) = 2 + 2

p(2) = 4