if p+m=6 and p^3+m^3=72, then what is the value of PM?
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Answer:
8
Step-by-step explanation:
p^3 + m^3 = (p+m)(p^2 + m^2 - pm) [BY a^3+b^3=(a+b)(a^2+b^2-ab)]
so , 72 = (6)( (p+m)^2- 3*pm) [BY using a^2+b^2=(a+b)^2-2ab]
so, 12 = 36-3*pm
3*pm=24
so, pm=8
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value of pm is zero.
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