Math, asked by Alexxx69, 9 months ago

if p+m=6 and p^3+m^3=72, then what is the value of PM?

Answers

Answered by Srichandralolla
0

Answer:

8

Step-by-step explanation:

p^3 + m^3 = (p+m)(p^2 + m^2 - pm)           [BY a^3+b^3=(a+b)(a^2+b^2-ab)]

so , 72 = (6)( (p+m)^2- 3*pm)                      [BY using a^2+b^2=(a+b)^2-2ab]

so, 12 =  36-3*pm

3*pm=24

so, pm=8

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Answered by Imstudentofu
0

value of pm is zero.

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