Question

If p(m) = m cube+ 2m square – m+ 10 then p(a) + p(- a) = ?​

Answer 1

Step-by-step explanation:

$p(m) = {m}^{3} + 2 {m}^{2} - m + 10$

Substituting a and -a in this polynomial or function, we get:

$p(a) = {a}^{3} + 2 {a}^{2} - a + 10$

$p ( - a) = { (- a)}^{3} + 2 { (- a)}^{2} - ( - a) + 10 = - {a}^{3} + 2 {a}^{2} + a + 10$

Therefore;

$p(a) + p( - a) = 4 {a}^{2} + 20$

I hope you are benefitted with this solution :)