if p (m) = m raise to 3 + 2m raise to 2 - M+10 then p (a) = ?
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Answer:
4a2+20
Step-by-step explanation:
p(m) = m3 + 2m2 – m + 10 Put m = a in the given polynomial. ∴ p(a) = a3 + 2a2 – a + 10 …(i) Put m = -a in the given polynomial. p(-a) = (-a)3 + 2(-a)2 – (-a) +10 ∴ p(-a) = -a3 + 2a2 + a + 10 …(ii) Adding (i) and (ii), p(a) + p(-a) = (a3 + 2a2 – a + 10) + (-a3 + 2a2 + a + 10) = a3 – a3 + 2a2 + 2a2 – a + a + 10 + 10 ∴ p(a) + p(-a) = 4a2 + 20
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