Question

if p(m)=m²—3 m+1,then find p(1)+p(—1)​

Answer 1

Answer

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$p(1) = 1 ^{3} - 3(1) + 1 \\ \\ = 1 - 3 + 1 \\ \\ = - 1..................eq(1)$

NOW

$p( - 1) = (- 1) ^{3} - 3( - 1) + 1 \\ \\ = - 1 + 3 + 1 \\ \\ = 3...........eq(2)$

From eq 1 and 2

$( - 1) + (3) \\ = 2$

hope it's help you ✔️

Answer 2

$\large\bf\underline{solution:-}$

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$p(1) = 1 ^{3} - 3(1) + 1 \\ \\ = 1 - 3 + 1 \</p><p></p><p>\ \\ = - 1..................eq(1)</p><p></p><p> </p><p>$

NOW

$</p><p>p( - 1) = (- 1) ^{3} - 3( - 1) + 1 \\ \\ = - 1 + 3 + 1 \\ \\ = 3...........eq(2)$

From eq 1 and 2

( -1 ) + (3)

= 2

hope it's help you ✔️