Question

if p(m)=m2-3m+1 then find p(1)+p(-1)​

Answer 1

$Given \: \boxed{\pink{ p(m) = m^{2} - 3m + 1 }}$

$i) p(1) = 1^{2} - 3 \times 1 + 1$

$= 1 - 3 + 1$

$= -2 + 1$

$= - 1 \: ---(1)$

$ii) p(-1) =(- 1 )^{2} - 3 \times (-1)+ 1$

$= 1 + 3 + 1$

$= 5\: ---(2)$

$\red{ Value \: of \: p(1) + p(-1) }$

$= -1 + 5$

$= 4$

Therefore.,

$\red{ Value \: of \: p(1) + p(-1) }\green { = 4 }$

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