If P = maximum value of sin α and Q = maximum value of cos β, then find the value of 6P – 3Q.
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maximum value of sin Alpha is 1 and also maximum value of cos beta is also one
given that p is equal to maximum value of sin alpha and q is the the maximum value of cos beta
=> p=1 and q=1
required,
6p - 3q=6(1)-3(1) =6-3=3
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