If p means are inserted between a and b prove that d = b-a/p+1
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imagine a co-ordinate axis with p uniform sections, the tiny line segments formed will be of p+1 in quantity, the length of that one segment is d .
therefore d(p+1) = b-a
rearrange to get .
comment if you didn't understand the analogy
therefore d(p+1) = b-a
rearrange to get .
comment if you didn't understand the analogy
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