If P=mi-2j+2k and Q=2i -nj+k are parallel to each other,then find m and n
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Answered by
114
two vector are parallel means cross product of its zero .
P =mi -2j +2k
Q =2i -nj + K
P×Q = (-2×1 +n×2)i -( m×1 - 2×2)j + ( -m×n +4)K = 0
so,
-2 +2n =0 → n = 1
m - 4 = 0→ m = 4
varify :-
-mn + 4 =0
-1×4 + 4 =0
so, m = 4 and n = 1
P =mi -2j +2k
Q =2i -nj + K
P×Q = (-2×1 +n×2)i -( m×1 - 2×2)j + ( -m×n +4)K = 0
so,
-2 +2n =0 → n = 1
m - 4 = 0→ m = 4
varify :-
-mn + 4 =0
-1×4 + 4 =0
so, m = 4 and n = 1
Answered by
0
Answer:
p vector × q vector = 0
by putting values nd solving we get
m = 4 and n = 1
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