Math, asked by tarangleo9485, 6 months ago

If p(not E)=0.16,what is the probability of E?

Answers

Answered by palchanchal878
0

Step-by-step explanation:

given = p ( not E) =0.16

p (E)+ p (not E) =1

p (E) + 0.16 = 1

p(E) = 1 - 0.16

p(E ) = 0.84

Answered by LiarHeart
0

Step-by-step explanation:

We know that the sum of the probabilities of all the elementary events of an experiment is 1.

If an experiment has two elementary events say E & not E then,

P(E)+P(notE)=1⟹P(notE)=1−P(E)

Given P(E)=0.05

∴P(notE)=1−0.05=0.95

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