If p(not E)=0.16,what is the probability of E?
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Step-by-step explanation:
given = p ( not E) =0.16
p (E)+ p (not E) =1
p (E) + 0.16 = 1
p(E) = 1 - 0.16
p(E ) = 0.84
Answered by
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Step-by-step explanation:
We know that the sum of the probabilities of all the elementary events of an experiment is 1.
If an experiment has two elementary events say E & not E then,
P(E)+P(notE)=1⟹P(notE)=1−P(E)
Given P(E)=0.05
∴P(notE)=1−0.05=0.95
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