Question

if P of x is equal to x square - 2 root 2 X + 1 then find the value of P of 2 into root 2​

Answer 1

hope this helps you.. :)

Answer 2

The required value is

$P(2\sqrt{2}) = 1$

Step-by-step explanation:

We are given the following in the question:

$P(x) = x^2-2\sqrt{2}x+1$

We have to find the value of P(x) at x = $2\sqrt{2}$

Putting x = $2\sqrt{2}$, we get,

$P(2\sqrt{2}) = (2\sqrt{2})^2-2\sqrt{2}(2\sqrt{2})+1\\P(2\sqrt{2}) = 8 - 8 + 1\\P(2\sqrt{2}) = 1$

is the required value.

#LearnMore

If x minus 1 is a factor of p( X )  equals to 2 x square minus kx + root 2 then find the value of k.

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