if P of X is equals to root 2 x cube minus 3 X square + 4 x minus 6 then find the value of P of root 2
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P(x) = √2x³ - 3x² + 4x - 6
P(√2) = √2(√2)³ - 3(√2)² + 4(√2) - 6
= √2×2√2 - 3×2 + 4√2 - 6
= 4 - 6 + 4√2 - 6
= 4√2 - 8
= 4(√2 - 2)
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