Math, asked by nenyamlani2005, 11 months ago

if P of X is equals to X raise to 7 8 7 - X raised to 7 86 + K is divided by X + 1 then K is equals to​

Answers

Answered by Anonymous
2

Step-by-step explanation:

Quantitative Aptitude: What is the remainder when (111…) + (222…) + (333…) + … + (777…) is divided by 37?

Ans: aaa = a*111 = a*3*37

= aaa is divisible by 37

= aaaa….. repeated 3n number of times is divisible by 37

= (1111…..1) 108 times is divisible by 37

Now, 1111…111 (110 times) = 111…..1100 (108 1s and 2 0s)+ 11

= Rem [1111…111 (110 times) /37] = 11

= Rem [2222…222 (110 times) /37] = 22

.

.

= Rem [7777…777 (110 times) /37] = 77

So, we can say that

Remainder when (111…) + (222…) + (333…) + … + (777…) is divided by 37

= Rem [11 + 22 + 33 + 44 + 55 + 66 + 77 / 37]

= Rem [308/37]

= 12

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