if P of X is equals to X raise to 7 8 7 - X raised to 7 86 + K is divided by X + 1 then K is equals to
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Quantitative Aptitude: What is the remainder when (111…) + (222…) + (333…) + … + (777…) is divided by 37?
Ans: aaa = a*111 = a*3*37
= aaa is divisible by 37
= aaaa….. repeated 3n number of times is divisible by 37
= (1111…..1) 108 times is divisible by 37
Now, 1111…111 (110 times) = 111…..1100 (108 1s and 2 0s)+ 11
= Rem [1111…111 (110 times) /37] = 11
= Rem [2222…222 (110 times) /37] = 22
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= Rem [7777…777 (110 times) /37] = 77
So, we can say that
Remainder when (111…) + (222…) + (333…) + … + (777…) is divided by 37
= Rem [11 + 22 + 33 + 44 + 55 + 66 + 77 / 37]
= Rem [308/37]
= 12
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