Question

if P of X is equals to x square minus x + 1 then P of 1 minus p minus of minus
1 is​

Answer 1

Step-by-step explanation:

$P(x) = {x}^{2} - x + 1 \\ \therefore \: P(1) = {1}^{2} - 1 + 1 \\ \therefore \: P(1) = {1}...(1) \\ next \\ P( - 1) = { (-1)}^{2} -( - 1) + 1 \\ \therefore \: P( - 1) = 1 + 1 + 1 \\\therefore \: P( - 1) = 3\\</p><p>\therefore \:P\{-(-1)\}=-3....(2)</p><p>\\Subtracting\: (2)\: from\: (1) \\ P(1) - P\{-(-1)\} = 1 - (-3) \\ \implies P(1) - P\{-(-1)\} = 1+3</p><p>\\ \implies P(1) - P\{-(-1)\} = 4$