Question

If p, p - 2, and 3p are in AP then find the value of p?

Answer 1

Answer:

$three \: \: terms \: \: in \: \: a.p. = > \\ \\ 2(p - 2) = p + 3p \\ \\ 2p - 4 = 4p \\ \\ - 2p = 4 \\ \\ p = - 2$

Answer 2

Answer:

-2

Step-by-step explanation:

t2-t1=t3-t2

here t2=p-2

t1=p

t3=3p

so the outcome is:(p-2)-p=3p-(p-2)

p=-2