Question

if p+q= 10 and pq = 21 find (1) p^2 - q^2 (2) p^3- q^3​

Answer 1

this is the answer

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

(p+q)^2 = p^2 + q^2 + 2pq

(p-q)^2 = p^2 + q^2 - 2pq

=> (p-q) ^2 = (p+q)^2 - 4pq

(p-q)^2 = (10)^2 - 4(21)

= 100 - 84

= 16

(p-q)^2 = (4)^2

p-q = 4

(1) p^2 - q^2 = (p+q) × (p-q)

= 10 × 4

= 40

=> p^2 + q^2 = (p+q)^2 - 2pq

= (10)^2 - 2(21)

= 100 - 42

p^2 + q^2 = 58

(2) p^3 - q^3 = (p-q)×( p^2 + q^2 + pq)

= (4)×(58+21)

= 4× 79

p^3 - q^3 = 316

HOPE YOU UNDERSTAND IT