if p+q=10 and pq=21,find 3(p²+q²)
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1
Answer:
p+q=10
squaring both side
(p+q)²= (10)²
p²+2pq+q²=100
p²+2(21) +q²=100
p²+24+q²=100
p²+q²=100-24
p²+q²=76
3(p²+q²) = 3(76)
= 228
Answered by
0
Answer:
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