Math, asked by harshita29251, 9 months ago

If p:q = 11:19 ,AB is parallel to CE then what is the value of p q r

Answers

Answered by shashipatidar83
8

Answer:

value of p is 11 ×=11×3= 33°

the value of q is 19 × = 19×3 =51°

the value of r is = 64°

Step-by-step explanation:

p:q = 11:19

let the value of P is 11 x

let the value of q is 19 x

and we have that <B= 90°

sum of all angles in the triangle is supplementary

11x + 19x + 90 = 180°

30x = 180°-90°

30x =90°

x= 3°

since AB parallels to CE

alternate angles are equal

so p+32°=r

32+ 32 = r

64 = r

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