If p:q = 11:19 ,AB is parallel to CE then what is the value of p q r
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Answer:
value of p is 11 ×=11×3= 33°
the value of q is 19 × = 19×3 =51°
the value of r is = 64°
Step-by-step explanation:
p:q = 11:19
let the value of P is 11 x
let the value of q is 19 x
and we have that <B= 90°
sum of all angles in the triangle is supplementary
11x + 19x + 90 = 180°
30x = 180°-90°
30x =90°
x= 3°
since AB parallels to CE
alternate angles are equal
so p+32°=r
32+ 32 = r
64 = r
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