if p+q=12 and p×q=22,then findp²+q²
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Answered by
0
Answer:
ANSWER
Given, p+q=12 and pq=22
We know that, (p+q)
2
=p
2
+q
2
+2pq ... (i)
By putting the given values in equation (i),
(12)
2
=p
2
+q
2
+2(22)
144=p
2
+q
2
+44
144—44=p
2
+q
2
100=p
2
+q
2
So. the value of p
2
+q
22
is 100.
Answered by
1
Answer:
The value of p^2+q^2p2+q2 is 100.
Step-by-step explanation:
Given information: p + q = 12 and pq = 22.
Using algebraic property:
(p+q)^2=p^2+2pq+q^2(p+q)2=p2+2pq+q2
(12)^2=p^2+2(22)+q^2(12)2=p2+2(22)+q2
144=p^2+44+q^2144=p2+44+q2
144-44=p^2+q^2144−44=p2+q2
100=p^2+q^2100=p2+q2
Therefore the value of p^2+q^2p2+q2 is 100.
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